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(1)   A lower numerical value of the Michaelis constant (Km) indicates a lower enzyme/transporter affinity for its substrate.
(2)   Assume that the reaction catalyzed by an enzyme follows Michaelis-Menten kinetics. The substrate concentration (Km, Michaelis constant) needed to reach 50% of the maximum reaction velocity (Vmax) is 25 μM. What substrate concentration is required to obtain at least 96% of the maximum reaction velocity?
(3)   Assume that the reaction catalyzed by an enzyme follows Michaelis-Menten kinetics. The substrate concentration (Km, Michaelis constant) needed to reach 50% of the maximum reaction velocity (Vmax) is 25 μM. What substrate concentration is required to obtain at least 98% of the maximum reaction velocity?
(4)   Assume that the reaction catalyzed by an enzyme follows Michaelis-Menten kinetics. The substrate concentration (Km, Michaelis constant) needed to reach 50% of the maximum reaction velocity (Vmax) is 25 μM. What substrate concentration is required to obtain at least 99% of the maximum reaction velocity?
(5)   Assume that the reaction catalyzed by an enzyme follows Michaelis-Menten kinetics. If at a substrate concentration of 100 nM, the reaction proceeds at 20% of the maximum reaction velocity (Vmax), what is the Michaelis constant (Km) for this substrate. Km is the substrate concentration needed to reach 50% of Vmax.
(6)   Assume that the reaction catalyzed by an enzyme follows Michaelis-Menten kinetics. If at a substrate concentration of 100 nM, the reaction proceeds at 10% of the maximum reaction velocity (Vmax), what is the Michaelis constant (Km) for this substrate. Km is the substrate concentration needed to reach 50% of Vmax.
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Posted: Tuesday, December 16, 2014
Last updated: Tuesday, March 11, 2025
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